Base | Representation |
---|---|
bin | 11101110101100001010011… |
… | …011010101001110101001011 |
3 | 122012121121221212010121211211 |
4 | 131311201103122221311023 |
5 | 114144412100010322103 |
6 | 1143030112224233551 |
7 | 36432264443162566 |
oct | 3565412332516513 |
9 | 565547855117754 |
10 | 131221240323403 |
11 | 388a16852606aa |
12 | 1287367ba6b8b7 |
13 | 582b1574b9a99 |
14 | 24591db5d74dd |
15 | 1028573d5336d |
hex | 7758536a9d4b |
131221240323403 has 4 divisors (see below), whose sum is σ = 131221269291600. Its totient is φ = 131221211355208.
The previous prime is 131221240323389. The next prime is 131221240323431. The reversal of 131221240323403 is 304323042122131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131221240323403 - 213 = 131221240315211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131221240323463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6053728 + ... + 17294221.
It is an arithmetic number, because the mean of its divisors is an integer number (32805317322900).
Almost surely, 2131221240323403 is an apocalyptic number.
131221240323403 is a deficient number, since it is larger than the sum of its proper divisors (28968197).
131221240323403 is an equidigital number, since it uses as much as digits as its factorization.
131221240323403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28968196.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 131221240323403 its reverse (304323042122131), we get a palindrome (435544282445534).
The spelling of 131221240323403 in words is "one hundred thirty-one trillion, two hundred twenty-one billion, two hundred forty million, three hundred twenty-three thousand, four hundred three".
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