Base | Representation |
---|---|
bin | 111101000110101110… |
… | …0101000101100000011 |
3 | 110112201002120000112021 |
4 | 1322031130220230003 |
5 | 4122220330104102 |
6 | 140141013142311 |
7 | 12323543362045 |
oct | 1721534505403 |
9 | 415632500467 |
10 | 131222113027 |
11 | 507185097a5 |
12 | 2152202a997 |
13 | c4b313c135 |
14 | 64cb913a95 |
15 | 36302bb137 |
hex | 1e8d728b03 |
131222113027 has 2 divisors, whose sum is σ = 131222113028. Its totient is φ = 131222113026.
The previous prime is 131222113007. The next prime is 131222113031. The reversal of 131222113027 is 720311222131.
It is a strong prime.
It is an emirp because it is prime and its reverse (720311222131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131222113027 - 215 = 131222080259 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131222112992 and 131222113010.
It is not a weakly prime, because it can be changed into another prime (131222113007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611056513 + 65611056514.
It is an arithmetic number, because the mean of its divisors is an integer number (65611056514).
Almost surely, 2131222113027 is an apocalyptic number.
131222113027 is a deficient number, since it is larger than the sum of its proper divisors (1).
131222113027 is an equidigital number, since it uses as much as digits as its factorization.
131222113027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 131222113027 its reverse (720311222131), we get a palindrome (851533335158).
The spelling of 131222113027 in words is "one hundred thirty-one billion, two hundred twenty-two million, one hundred thirteen thousand, twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •