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131222113027 is a prime number
BaseRepresentation
bin111101000110101110…
…0101000101100000011
3110112201002120000112021
41322031130220230003
54122220330104102
6140141013142311
712323543362045
oct1721534505403
9415632500467
10131222113027
11507185097a5
122152202a997
13c4b313c135
1464cb913a95
1536302bb137
hex1e8d728b03

131222113027 has 2 divisors, whose sum is σ = 131222113028. Its totient is φ = 131222113026.

The previous prime is 131222113007. The next prime is 131222113031. The reversal of 131222113027 is 720311222131.

It is a strong prime.

It is an emirp because it is prime and its reverse (720311222131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131222113027 - 215 = 131222080259 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131222112992 and 131222113010.

It is not a weakly prime, because it can be changed into another prime (131222113007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611056513 + 65611056514.

It is an arithmetic number, because the mean of its divisors is an integer number (65611056514).

Almost surely, 2131222113027 is an apocalyptic number.

131222113027 is a deficient number, since it is larger than the sum of its proper divisors (1).

131222113027 is an equidigital number, since it uses as much as digits as its factorization.

131222113027 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 131222113027 its reverse (720311222131), we get a palindrome (851533335158).

The spelling of 131222113027 in words is "one hundred thirty-one billion, two hundred twenty-two million, one hundred thirteen thousand, twenty-seven".