Base | Representation |
---|---|
bin | 11101110101100010000111… |
… | …111011011011010100011011 |
3 | 122012121201020020220101121211 |
4 | 131311202013323123110123 |
5 | 114144420401030024242 |
6 | 1143030335455243551 |
7 | 36432325331464024 |
oct | 3565420773332433 |
9 | 565551206811554 |
10 | 131222121329947 |
11 | 388a1a9759a98a |
12 | 12873886b195b7 |
13 | 582b267b9322b |
14 | 245928260bc4b |
15 | 10285c637c317 |
hex | 775887edb51b |
131222121329947 has 2 divisors, whose sum is σ = 131222121329948. Its totient is φ = 131222121329946.
The previous prime is 131222121329917. The next prime is 131222121329951. The reversal of 131222121329947 is 749923121222131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131222121329947 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131222121329947.
It is not a weakly prime, because it can be changed into another prime (131222121329917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611060664973 + 65611060664974.
It is an arithmetic number, because the mean of its divisors is an integer number (65611060664974).
Almost surely, 2131222121329947 is an apocalyptic number.
131222121329947 is a deficient number, since it is larger than the sum of its proper divisors (1).
131222121329947 is an equidigital number, since it uses as much as digits as its factorization.
131222121329947 is an evil number, because the sum of its binary digits is even.
The product of its digits is 653184, while the sum is 49.
The spelling of 131222121329947 in words is "one hundred thirty-one trillion, two hundred twenty-two billion, one hundred twenty-one million, three hundred twenty-nine thousand, nine hundred forty-seven".
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