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131222121329947 is a prime number
BaseRepresentation
bin11101110101100010000111…
…111011011011010100011011
3122012121201020020220101121211
4131311202013323123110123
5114144420401030024242
61143030335455243551
736432325331464024
oct3565420773332433
9565551206811554
10131222121329947
11388a1a9759a98a
1212873886b195b7
13582b267b9322b
14245928260bc4b
1510285c637c317
hex775887edb51b

131222121329947 has 2 divisors, whose sum is σ = 131222121329948. Its totient is φ = 131222121329946.

The previous prime is 131222121329917. The next prime is 131222121329951. The reversal of 131222121329947 is 749923121222131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131222121329947 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131222121329947.

It is not a weakly prime, because it can be changed into another prime (131222121329917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611060664973 + 65611060664974.

It is an arithmetic number, because the mean of its divisors is an integer number (65611060664974).

Almost surely, 2131222121329947 is an apocalyptic number.

131222121329947 is a deficient number, since it is larger than the sum of its proper divisors (1).

131222121329947 is an equidigital number, since it uses as much as digits as its factorization.

131222121329947 is an evil number, because the sum of its binary digits is even.

The product of its digits is 653184, while the sum is 49.

The spelling of 131222121329947 in words is "one hundred thirty-one trillion, two hundred twenty-two billion, one hundred twenty-one million, three hundred twenty-nine thousand, nine hundred forty-seven".