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13122227390497 is a prime number
BaseRepresentation
bin1011111011110100000110…
…1100111100100000100001
31201110110202120220022010021
42332331001230330200201
53204443310202443442
643524133521433441
72523023012312551
oct276750154744041
951413676808107
1013122227390497
1141aa1182a2305
12157b21349b881
13742561474414
143351950d9161
1517b514e69e67
hexbef41b3c821

13122227390497 has 2 divisors, whose sum is σ = 13122227390498. Its totient is φ = 13122227390496.

The previous prime is 13122227390407. The next prime is 13122227390513. The reversal of 13122227390497 is 79409372222131.

13122227390497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11801863227456 + 1320364163041 = 3435384^2 + 1149071^2 .

It is a cyclic number.

It is not a de Polignac number, because 13122227390497 - 211 = 13122227388449 is a prime.

It is a super-2 number, since 2×131222273904972 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13122227390407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561113695248 + 6561113695249.

It is an arithmetic number, because the mean of its divisors is an integer number (6561113695249).

Almost surely, 213122227390497 is an apocalyptic number.

It is an amenable number.

13122227390497 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122227390497 is an equidigital number, since it uses as much as digits as its factorization.

13122227390497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2286144, while the sum is 52.

The spelling of 13122227390497 in words is "thirteen trillion, one hundred twenty-two billion, two hundred twenty-seven million, three hundred ninety thousand, four hundred ninety-seven".