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1312223033113 = 5412425550893
BaseRepresentation
bin10011000110000110100…
…101100111011100011001
311122110002002010212111021
4103012012211213130121
5132444413044024423
62442454341402441
7163543052513416
oct23060645473431
94573062125437
101312223033113
11466568768953
12192398a09421
139698551c105
1447724a6310d
152420204e95d
hex13186967719

1312223033113 has 4 divisors (see below), whose sum is σ = 1314648584548. Its totient is φ = 1309797481680.

The previous prime is 1312223033101. The next prime is 1312223033117. The reversal of 1312223033113 is 3113303222131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 188904975424 + 1123318057689 = 434632^2 + 1059867^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312223033113 - 25 = 1312223033081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1312223033117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1212774906 + ... + 1212775987.

It is an arithmetic number, because the mean of its divisors is an integer number (328662146137).

Almost surely, 21312223033113 is an apocalyptic number.

It is an amenable number.

1312223033113 is a deficient number, since it is larger than the sum of its proper divisors (2425551435).

1312223033113 is an equidigital number, since it uses as much as digits as its factorization.

1312223033113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2425551434.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1312223033113 its reverse (3113303222131), we get a palindrome (4425526255244).

The spelling of 1312223033113 in words is "one trillion, three hundred twelve billion, two hundred twenty-three million, thirty-three thousand, one hundred thirteen".

Divisors: 1 541 2425550893 1312223033113