131222310041441 has 4 divisors (see below), whose sum is σ = 131224135510272. Its totient is φ = 131220484572612.

The previous prime is 131222310041353. The next prime is 131222310041477. The reversal of 131222310041441 is 144140013222131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131222310041441 - 2¹⁴ = 131222310025057 is a prime.

It is a super-2 number, since 2×131222310041441² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131222310041941) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 912626585 + ... + 912770358.

It is an arithmetic number, because the mean of its divisors is an integer number (32806033877568).

Almost surely, 2^{131222310041441} is an apocalyptic number.

It is an amenable number.

131222310041441 is a deficient number, since it is larger than the sum of its proper divisors (1825468831).

131222310041441 is an equidigital number, since it uses as much as digits as its factorization.

131222310041441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1825468830.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 131222310041441 its reverse (144140013222131), we get a palindrome (275362323263572).

The spelling of 131222310041441 in words is "one hundred thirty-one trillion, two hundred twenty-two billion, three hundred ten million, forty-one thousand, four hundred forty-one".