13122232042081 has 2 divisors, whose sum is σ = 13122232042082. Its totient is φ = 13122232042080.

The previous prime is 13122232042057. The next prime is 13122232042111. The reversal of 13122232042081 is 18024023222131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7683518311056 + 5438713731025 = 2771916^2 + 2332105^2 .

It is a cyclic number.

It is not a de Polignac number, because 13122232042081 - 2¹⁹ = 13122231517793 is a prime.

It is a super-4 number, since 4×13122232042081⁴ (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (13122232042181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561116021040 + 6561116021041.

It is an arithmetic number, because the mean of its divisors is an integer number (6561116021041).

Almost surely, 2^{13122232042081} is an apocalyptic number.

It is an amenable number.

13122232042081 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122232042081 is an equidigital number, since it uses as much as digits as its factorization.

13122232042081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9216, while the sum is 31.

The spelling of 13122232042081 in words is "thirteen trillion, one hundred twenty-two billion, two hundred thirty-two million, forty-two thousand, eighty-one".