Base | Representation |
---|---|
bin | 11101110101100010010011… |
… | …111001010110111000011001 |
3 | 122012121201202020201021122221 |
4 | 131311202103321112320121 |
5 | 114144421303430122243 |
6 | 1143030411430544041 |
7 | 36432333320225341 |
oct | 3565422371267031 |
9 | 565551666637587 |
10 | 131222322114073 |
11 | 388a208a968a83 |
12 | 12873922208021 |
13 | 582b29a6633c8 |
14 | 24592a1155d21 |
15 | 10285d8cddbed |
hex | 775893e56e19 |
131222322114073 has 2 divisors, whose sum is σ = 131222322114074. Its totient is φ = 131222322114072.
The previous prime is 131222322114031. The next prime is 131222322114119. The reversal of 131222322114073 is 370411223222131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 75291248764809 + 55931073349264 = 8677053^2 + 7478708^2 .
It is a cyclic number.
It is not a de Polignac number, because 131222322114073 - 237 = 131084883160601 is a prime.
It is not a weakly prime, because it can be changed into another prime (131222322114673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611161057036 + 65611161057037.
It is an arithmetic number, because the mean of its divisors is an integer number (65611161057037).
Almost surely, 2131222322114073 is an apocalyptic number.
It is an amenable number.
131222322114073 is a deficient number, since it is larger than the sum of its proper divisors (1).
131222322114073 is an equidigital number, since it uses as much as digits as its factorization.
131222322114073 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 34.
The spelling of 131222322114073 in words is "one hundred thirty-one trillion, two hundred twenty-two billion, three hundred twenty-two million, one hundred fourteen thousand, seventy-three".
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