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13122300432251 is a prime number
BaseRepresentation
bin1011111011110100011000…
…0011100100111101111011
31201110110221200100012120102
42332331012003210331323
53204443432402313001
643524145051150015
72523024560205353
oct276750603447573
951413850305512
1013122300432251
1141aa15555069a
12157b233a4530b
137425736395aa
143351a0aadb63
1517b51b596e6b
hexbef460e4f7b

13122300432251 has 2 divisors, whose sum is σ = 13122300432252. Its totient is φ = 13122300432250.

The previous prime is 13122300432221. The next prime is 13122300432301. The reversal of 13122300432251 is 15223400322131.

It is a weak prime.

It is an emirp because it is prime and its reverse (15223400322131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13122300432251 - 214 = 13122300415867 is a prime.

It is a super-3 number, since 3×131223004322513 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13122300432221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561150216125 + 6561150216126.

It is an arithmetic number, because the mean of its divisors is an integer number (6561150216126).

Almost surely, 213122300432251 is an apocalyptic number.

13122300432251 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122300432251 is an equidigital number, since it uses as much as digits as its factorization.

13122300432251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 13122300432251 its reverse (15223400322131), we get a palindrome (28345700754382).

The spelling of 13122300432251 in words is "thirteen trillion, one hundred twenty-two billion, three hundred million, four hundred thirty-two thousand, two hundred fifty-one".