Base | Representation |
---|---|
bin | 1011111011110100011000… |
… | …0011100100111101111011 |
3 | 1201110110221200100012120102 |
4 | 2332331012003210331323 |
5 | 3204443432402313001 |
6 | 43524145051150015 |
7 | 2523024560205353 |
oct | 276750603447573 |
9 | 51413850305512 |
10 | 13122300432251 |
11 | 41aa15555069a |
12 | 157b233a4530b |
13 | 7425736395aa |
14 | 3351a0aadb63 |
15 | 17b51b596e6b |
hex | bef460e4f7b |
13122300432251 has 2 divisors, whose sum is σ = 13122300432252. Its totient is φ = 13122300432250.
The previous prime is 13122300432221. The next prime is 13122300432301. The reversal of 13122300432251 is 15223400322131.
It is a weak prime.
It is an emirp because it is prime and its reverse (15223400322131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13122300432251 - 214 = 13122300415867 is a prime.
It is a super-3 number, since 3×131223004322513 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13122300432221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561150216125 + 6561150216126.
It is an arithmetic number, because the mean of its divisors is an integer number (6561150216126).
Almost surely, 213122300432251 is an apocalyptic number.
13122300432251 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122300432251 is an equidigital number, since it uses as much as digits as its factorization.
13122300432251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 13122300432251 its reverse (15223400322131), we get a palindrome (28345700754382).
The spelling of 13122300432251 in words is "thirteen trillion, one hundred twenty-two billion, three hundred million, four hundred thirty-two thousand, two hundred fifty-one".
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