Base | Representation |
---|---|
bin | 1011111011110100011000… |
… | …1101100101000101000111 |
3 | 1201110110221212021102010211 |
4 | 2332331012031211011013 |
5 | 3204443434040213101 |
6 | 43524145223300251 |
7 | 2523024621405364 |
oct | 276750615450507 |
9 | 51413855242124 |
10 | 13122303054151 |
11 | 41aa156a81555 |
12 | 157b2348aa687 |
13 | 742574046b05 |
14 | 3351a119346b |
15 | 17b51b913c51 |
hex | bef46365147 |
13122303054151 has 16 divisors (see below), whose sum is σ = 13746157867008. Its totient is φ = 12511816725600.
The previous prime is 13122303054149. The next prime is 13122303054187. The reversal of 13122303054151 is 15145030322131.
It is a cyclic number.
It is not a de Polignac number, because 13122303054151 - 21 = 13122303054149 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13122303054121) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6003940 + ... + 7892521.
It is an arithmetic number, because the mean of its divisors is an integer number (859134866688).
Almost surely, 213122303054151 is an apocalyptic number.
13122303054151 is a deficient number, since it is larger than the sum of its proper divisors (623854812857).
13122303054151 is a wasteful number, since it uses less digits than its factorization.
13122303054151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13896942.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 13122303054151 its reverse (15145030322131), we get a palindrome (28267333376282).
The spelling of 13122303054151 in words is "thirteen trillion, one hundred twenty-two billion, three hundred three million, fifty-four thousand, one hundred fifty-one".
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