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131223053331553 is a prime number
BaseRepresentation
bin11101110101100010111111…
…011110101110110001100001
3122012121210122012121222110211
4131311202333132232301201
5114144424303123102203
61143031012151254121
736432360406405621
oct3565427736566141
9565553565558424
10131223053331553
11388a242569a547
1212873aa707a341
13582b385cb2981
1424593302d8881
15102862d0cac6d
hex7758bf7aec61

131223053331553 has 2 divisors, whose sum is σ = 131223053331554. Its totient is φ = 131223053331552.

The previous prime is 131223053331547. The next prime is 131223053331583. The reversal of 131223053331553 is 355133350322131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106741813917649 + 24481239413904 = 10331593^2 + 4947852^2 .

It is an emirp because it is prime and its reverse (355133350322131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131223053331553 - 213 = 131223053323361 is a prime.

It is not a weakly prime, because it can be changed into another prime (131223053331583) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611526665776 + 65611526665777.

It is an arithmetic number, because the mean of its divisors is an integer number (65611526665777).

Almost surely, 2131223053331553 is an apocalyptic number.

It is an amenable number.

131223053331553 is a deficient number, since it is larger than the sum of its proper divisors (1).

131223053331553 is an equidigital number, since it uses as much as digits as its factorization.

131223053331553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 364500, while the sum is 40.

The spelling of 131223053331553 in words is "one hundred thirty-one trillion, two hundred twenty-three billion, fifty-three million, three hundred thirty-one thousand, five hundred fifty-three".