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1312231121281 is a prime number
BaseRepresentation
bin10011000110000111000…
…100011110000110000001
311122110002122100210101001
4103012013010132012001
5132444422131340111
62442455231012001
7163543211331163
oct23060704360601
94573078323331
101312231121281
11466572292693
1219239b66a001
13969870c1702
1447725b6a933
1524202aeb1c1
hex1318711e181

1312231121281 has 2 divisors, whose sum is σ = 1312231121282. Its totient is φ = 1312231121280.

The previous prime is 1312231121263. The next prime is 1312231121293. The reversal of 1312231121281 is 1821211322131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1174156452225 + 138074669056 = 1083585^2 + 371584^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312231121281 - 211 = 1312231119233 is a prime.

It is a super-2 number, since 2×13122311212812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1312231121381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656115560640 + 656115560641.

It is an arithmetic number, because the mean of its divisors is an integer number (656115560641).

Almost surely, 21312231121281 is an apocalyptic number.

It is an amenable number.

1312231121281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312231121281 is an equidigital number, since it uses as much as digits as its factorization.

1312231121281 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 28.

The spelling of 1312231121281 in words is "one trillion, three hundred twelve billion, two hundred thirty-one million, one hundred twenty-one thousand, two hundred eighty-one".