Base | Representation |
---|---|
bin | 1011111011110100011010… |
… | …1111110100101100100011 |
3 | 1201110110222111011111002010 |
4 | 2332331012233310230203 |
5 | 3204443443334443021 |
6 | 43524150143524003 |
7 | 2523025060614111 |
oct | 276750657645443 |
9 | 51413874144063 |
10 | 13122312031011 |
11 | 41aa161052a47 |
12 | 157b2378b9603 |
13 | 742575b6aa71 |
14 | 3351a244cab1 |
15 | 17b51c5d8976 |
hex | bef46bf4b23 |
13122312031011 has 4 divisors (see below), whose sum is σ = 17496416041352. Its totient is φ = 8748208020672.
The previous prime is 13122312031009. The next prime is 13122312031033. The reversal of 13122312031011 is 11013021322131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13122312031011 - 21 = 13122312031009 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13122312031061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2187052005166 + ... + 2187052005171.
It is an arithmetic number, because the mean of its divisors is an integer number (4374104010338).
Almost surely, 213122312031011 is an apocalyptic number.
13122312031011 is a deficient number, since it is larger than the sum of its proper divisors (4374104010341).
13122312031011 is an equidigital number, since it uses as much as digits as its factorization.
13122312031011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4374104010340.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 13122312031011 its reverse (11013021322131), we get a palindrome (24135333353142).
The spelling of 13122312031011 in words is "thirteen trillion, one hundred twenty-two billion, three hundred twelve million, thirty-one thousand, eleven".
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