Base | Representation |
---|---|
bin | 10011000110000111001… |
… | …100000110110100111010 |
3 | 11122110002210010111101121 |
4 | 103012013030012310322 |
5 | 132444423134420010 |
6 | 2442455341535454 |
7 | 163543234336366 |
oct | 23060714066472 |
9 | 4573083114347 |
10 | 1312233123130 |
11 | 46657342a706 |
12 | 1923a027458a |
13 | 96987642937 |
14 | 4772612c2a6 |
15 | 24202d943da |
hex | 13187306d3a |
1312233123130 has 64 divisors (see below), whose sum is σ = 2425670997120. Its totient is φ = 510814080000.
The previous prime is 1312233123107. The next prime is 1312233123151. The reversal of 1312233123130 is 313213322131.
It is a junction number, because it is equal to n+sod(n) for n = 1312233123095 and 1312233123104.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 571280142 + ... + 571282438.
It is an arithmetic number, because the mean of its divisors is an integer number (37901109330).
Almost surely, 21312233123130 is an apocalyptic number.
1312233123130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1312233123130 is a deficient number, since it is larger than the sum of its proper divisors (1113437873990).
1312233123130 is a wasteful number, since it uses less digits than its factorization.
1312233123130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5215.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1312233123130 its reverse (313213322131), we get a palindrome (1625446445261).
The spelling of 1312233123130 in words is "one trillion, three hundred twelve billion, two hundred thirty-three million, one hundred twenty-three thousand, one hundred thirty".
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