131223320034041 has 4 divisors (see below), whose sum is σ = 131223498705552. Its totient is φ = 131223141362532.

The previous prime is 131223320034019. The next prime is 131223320034067. The reversal of 131223320034041 is 140430023322131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131223320034041 - 2⁶ = 131223320033977 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131223320033995 and 131223320034013.

It is not an unprimeable number, because it can be changed into a prime (131223320034241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88229531 + ... + 89704496.

It is an arithmetic number, because the mean of its divisors is an integer number (32805874676388).

Almost surely, 2^{131223320034041} is an apocalyptic number.

It is an amenable number.

131223320034041 is a deficient number, since it is larger than the sum of its proper divisors (178671511).

131223320034041 is an equidigital number, since it uses as much as digits as its factorization.

131223320034041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 178671510.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 131223320034041 its reverse (140430023322131), we get a palindrome (271653343356172).

The spelling of 131223320034041 in words is "one hundred thirty-one trillion, two hundred twenty-three billion, three hundred twenty million, thirty-four thousand, forty-one".