Base | Representation |
---|---|
bin | 1011111011110100100010… |
… | …0011000110111000001100 |
3 | 1201110111001121000212112122 |
4 | 2332331020203012320030 |
5 | 3204444024104031134 |
6 | 43524153143352112 |
7 | 2523025605523064 |
oct | 276751043067014 |
9 | 51414047025478 |
10 | 13122342252044 |
11 | 41aa177114503 |
12 | 157b245a52638 |
13 | 74257c1bc52c |
14 | 3351a64783a4 |
15 | 17b5200a802e |
hex | bef488c6e0c |
13122342252044 has 12 divisors (see below), whose sum is σ = 22964542036800. Its totient is φ = 6561044527248.
The previous prime is 13122342252029. The next prime is 13122342252053. The reversal of 13122342252044 is 44025224322131.
13122342252044 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×131223422520443 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13122342251995 and 13122342252013.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31416284 + ... + 31831235.
It is an arithmetic number, because the mean of its divisors is an integer number (1913711836400).
Almost surely, 213122342252044 is an apocalyptic number.
It is an amenable number.
13122342252044 is a deficient number, since it is larger than the sum of its proper divisors (9842199784756).
13122342252044 is a wasteful number, since it uses less digits than its factorization.
13122342252044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63299392 (or 63299390 counting only the distinct ones).
The product of its (nonzero) digits is 92160, while the sum is 35.
Adding to 13122342252044 its reverse (44025224322131), we get a palindrome (57147566574175).
The spelling of 13122342252044 in words is "thirteen trillion, one hundred twenty-two billion, three hundred forty-two million, two hundred fifty-two thousand, forty-four".
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