Base | Representation |
---|---|
bin | 1011111011110100100010… |
… | …0011110000101001011011 |
3 | 1201110111001121100120020012 |
4 | 2332331020203300221123 |
5 | 3204444024130020011 |
6 | 43524153151152135 |
7 | 2523025610134634 |
oct | 276751043605133 |
9 | 51414047316205 |
10 | 13122342423131 |
11 | 41aa177220aa7 |
12 | 157b245b1564b |
13 | 74257c24c376 |
14 | 3351a64c088b |
15 | 17b5200dda8b |
hex | bef488f0a5b |
13122342423131 has 2 divisors, whose sum is σ = 13122342423132. Its totient is φ = 13122342423130.
The previous prime is 13122342423121. The next prime is 13122342423149. The reversal of 13122342423131 is 13132424322131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13122342423131 - 26 = 13122342423067 is a prime.
It is a super-2 number, since 2×131223424231312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13122342423121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561171211565 + 6561171211566.
It is an arithmetic number, because the mean of its divisors is an integer number (6561171211566).
Almost surely, 213122342423131 is an apocalyptic number.
13122342423131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122342423131 is an equidigital number, since it uses as much as digits as its factorization.
13122342423131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20736, while the sum is 32.
Adding to 13122342423131 its reverse (13132424322131), we get a palindrome (26254766745262).
The spelling of 13122342423131 in words is "thirteen trillion, one hundred twenty-two billion, three hundred forty-two million, four hundred twenty-three thousand, one hundred thirty-one".
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