Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0010101001011001001100 |
3 | 1201110111020112222022102211 |
4 | 2332331030302221121030 |
5 | 3204444200314400234 |
6 | 43524204205200204 |
7 | 2523030431542666 |
oct | 276751462513114 |
9 | 51414215868384 |
10 | 13122413434444 |
11 | 41aa203312936 |
12 | 157b265860064 |
13 | 742590b832b2 |
14 | 3351b1ac7536 |
15 | 17b526469164 |
hex | bef4cca964c |
13122413434444 has 48 divisors (see below), whose sum is σ = 23612261944320. Its totient is φ = 6379067534400.
The previous prime is 13122413434411. The next prime is 13122413434447. The reversal of 13122413434444 is 44443431422131.
It is a junction number, because it is equal to n+sod(n) for n = 13122413434397 and 13122413434406.
It is not an unprimeable number, because it can be changed into a prime (13122413434447) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6863269 + ... + 8564419.
It is an arithmetic number, because the mean of its divisors is an integer number (491922123840).
Almost surely, 213122413434444 is an apocalyptic number.
It is an amenable number.
13122413434444 is a deficient number, since it is larger than the sum of its proper divisors (10489848509876).
13122413434444 is a wasteful number, since it uses less digits than its factorization.
13122413434444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1701598 (or 1701596 counting only the distinct ones).
The product of its digits is 442368, while the sum is 40.
Adding to 13122413434444 its reverse (44443431422131), we get a palindrome (57565844856575).
The spelling of 13122413434444 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirteen million, four hundred thirty-four thousand, four hundred forty-four".
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