Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0100110011110011111011 |
3 | 1201110111020121001010011022 |
4 | 2332331030310303303323 |
5 | 3204444200441021103 |
6 | 43524204225253055 |
7 | 2523030436423640 |
oct | 276751464636373 |
9 | 51414217033138 |
10 | 13122414001403 |
11 | 41aa20366a8a3 |
12 | 157b265a9418b |
13 | 742591021385 |
14 | 3351b1bd3dc7 |
15 | 17b52652c138 |
hex | bef4cd33cfb |
13122414001403 has 16 divisors (see below), whose sum is σ = 15514933371840. Its totient is φ = 10864799232000.
The previous prime is 13122414001379. The next prime is 13122414001421. The reversal of 13122414001403 is 30410041422131.
It is not a de Polignac number, because 13122414001403 - 214 = 13122413985019 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13122414001453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 226320998 + ... + 226378971.
It is an arithmetic number, because the mean of its divisors is an integer number (969683335740).
Almost surely, 213122414001403 is an apocalyptic number.
13122414001403 is a deficient number, since it is larger than the sum of its proper divisors (2392519370437).
13122414001403 is a wasteful number, since it uses less digits than its factorization.
13122414001403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 452700118.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 13122414001403 its reverse (30410041422131), we get a palindrome (43532455423534).
The spelling of 13122414001403 in words is "thirteen trillion, one hundred twenty-two billion, four hundred fourteen million, one thousand, four hundred three".
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