131224413244033 has 4 divisors (see below), whose sum is σ = 131227751222788. Its totient is φ = 131221075265280.

The previous prime is 131224413244031. The next prime is 131224413244049. The reversal of 131224413244033 is 330442314422131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 45505183537009 + 85719229707024 = 6745753^2 + 9258468^2 .

It is a cyclic number.

It is not a de Polignac number, because 131224413244033 - 2¹ = 131224413244031 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131224413243983 and 131224413244001.

It is not an unprimeable number, because it can be changed into a prime (131224413244031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1668930408 + ... + 1669009033.

It is an arithmetic number, because the mean of its divisors is an integer number (32806937805697).

Almost surely, 2^{131224413244033} is an apocalyptic number.

It is an amenable number.

131224413244033 is a deficient number, since it is larger than the sum of its proper divisors (3337978755).

131224413244033 is an equidigital number, since it uses as much as digits as its factorization.

131224413244033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3337978754.

The product of its (nonzero) digits is 165888, while the sum is 37.

Adding to 131224413244033 its reverse (330442314422131), we get a palindrome (461666727666164).

The spelling of 131224413244033 in words is "one hundred thirty-one trillion, two hundred twenty-four billion, four hundred thirteen million, two hundred forty-four thousand, thirty-three".