Base | Representation |
---|---|
bin | 1011111011110100111100… |
… | …1010110011001011010001 |
3 | 1201110111100100000201200111 |
4 | 2332331033022303023101 |
5 | 3204444241022223101 |
6 | 43524212152121321 |
7 | 2523031424554405 |
oct | 276751712631321 |
9 | 51414310021614 |
10 | 13122453320401 |
11 | 41aa223885837 |
12 | 157b277096241 |
13 | 742599209c59 |
14 | 3351b710b105 |
15 | 17b529be7251 |
hex | bef4f2b32d1 |
13122453320401 has 2 divisors, whose sum is σ = 13122453320402. Its totient is φ = 13122453320400.
The previous prime is 13122453320377. The next prime is 13122453320429. The reversal of 13122453320401 is 10402335422131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13109468490000 + 12984830401 = 3620700^2 + 113951^2 .
It is a cyclic number.
It is not a de Polignac number, because 13122453320401 - 221 = 13122451223249 is a prime.
It is a super-2 number, since 2×131224533204012 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13122453321401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561226660200 + 6561226660201.
It is an arithmetic number, because the mean of its divisors is an integer number (6561226660201).
Almost surely, 213122453320401 is an apocalyptic number.
It is an amenable number.
13122453320401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122453320401 is an equidigital number, since it uses as much as digits as its factorization.
13122453320401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 13122453320401 its reverse (10402335422131), we get a palindrome (23524788742532).
The spelling of 13122453320401 in words is "thirteen trillion, one hundred twenty-two billion, four hundred fifty-three million, three hundred twenty thousand, four hundred one".
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