Base | Representation |
---|---|
bin | 11000011100010100… |
… | …11111011100001011 |
3 | 1020212112100202022121 |
4 | 30032022133130023 |
5 | 203333332030011 |
6 | 10010045232111 |
7 | 643121456041 |
oct | 141612373413 |
9 | 36775322277 |
10 | 13122533131 |
11 | 5624367404 |
12 | 2662862637 |
13 | 13118a4906 |
14 | 8c6b44391 |
15 | 51c0a7e71 |
hex | 30e29f70b |
13122533131 has 2 divisors, whose sum is σ = 13122533132. Its totient is φ = 13122533130.
The previous prime is 13122533113. The next prime is 13122533161. The reversal of 13122533131 is 13133522131.
Together with previous prime (13122533113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13122533131 - 213 = 13122524939 is a prime.
It is a super-2 number, since 2×131225331312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13122533096 and 13122533105.
It is not a weakly prime, because it can be changed into another prime (13122533161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561266565 + 6561266566.
It is an arithmetic number, because the mean of its divisors is an integer number (6561266566).
Almost surely, 213122533131 is an apocalyptic number.
13122533131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122533131 is an equidigital number, since it uses as much as digits as its factorization.
13122533131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1620, while the sum is 25.
The spelling of 13122533131 in words is "thirteen billion, one hundred twenty-two million, five hundred thirty-three thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.107 sec. • engine limits •