Base | Representation |
---|---|
bin | 10011000110001000111… |
… | …011001100001011101011 |
3 | 11122110011210220221102012 |
4 | 103012020323030023223 |
5 | 133000003113234201 |
6 | 2442502302030135 |
7 | 163544040011204 |
oct | 23061073141353 |
9 | 4573153827365 |
10 | 1312262243051 |
11 | 466588909961 |
12 | 1923a9b7834b |
13 | 9699069a166 |
14 | 47729d4c5ab |
15 | 242056e75bb |
hex | 13188ecc2eb |
1312262243051 has 4 divisors (see below), whose sum is σ = 1328873157600. Its totient is φ = 1295651328504.
The previous prime is 1312262243003. The next prime is 1312262243053. The reversal of 1312262243051 is 1503422622131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312262243051 - 218 = 1312261980907 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1312262242999 and 1312262243017.
It is not an unprimeable number, because it can be changed into a prime (1312262243053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8305457156 + ... + 8305457313.
It is an arithmetic number, because the mean of its divisors is an integer number (332218289400).
Almost surely, 21312262243051 is an apocalyptic number.
1312262243051 is a deficient number, since it is larger than the sum of its proper divisors (16610914549).
1312262243051 is an equidigital number, since it uses as much as digits as its factorization.
1312262243051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16610914548.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 1312262243051 its reverse (1503422622131), we get a palindrome (2815684865182).
The spelling of 1312262243051 in words is "one trillion, three hundred twelve billion, two hundred sixty-two million, two hundred forty-three thousand, fifty-one".
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