Base | Representation |
---|---|
bin | 1011111011110101101001… |
… | …1001001011110001001011 |
3 | 1201110111211110101101022211 |
4 | 2332331122121023301023 |
5 | 3210000132224444043 |
6 | 43524243000325551 |
7 | 2523036202344562 |
oct | 276753231136113 |
9 | 51414743341284 |
10 | 13122641640523 |
11 | 41aa3101104a8 |
12 | 157b30a1738b7 |
13 | 7425c9234b8c |
14 | 3351d412cbd9 |
15 | 17b53b4e5a9d |
hex | bef5a64bc4b |
13122641640523 has 4 divisors (see below), whose sum is σ = 13123090598688. Its totient is φ = 13122192682360.
The previous prime is 13122641640439. The next prime is 13122641640539. The reversal of 13122641640523 is 32504614622131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13122641640523 - 29 = 13122641640011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13122641640623) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224435236 + ... + 224493697.
It is an arithmetic number, because the mean of its divisors is an integer number (3280772649672).
Almost surely, 213122641640523 is an apocalyptic number.
13122641640523 is a deficient number, since it is larger than the sum of its proper divisors (448958165).
13122641640523 is an equidigital number, since it uses as much as digits as its factorization.
13122641640523 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 448958164.
The product of its (nonzero) digits is 207360, while the sum is 40.
The spelling of 13122641640523 in words is "thirteen trillion, one hundred twenty-two billion, six hundred forty-one million, six hundred forty thousand, five hundred twenty-three".
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