Search a number
-
+
131230012000001 is a prime number
BaseRepresentation
bin11101110101101001011110…
…001111111100011100000001
3122012122110121011120222000212
4131311221132033330130001
5114200033031033000001
61143034122451523505
736433025014203005
oct3565513617743401
9565573534528025
10131230012000001
11388a5376684102
12128753095b9595
13582bc24876c75
1424597d0576705
1510288d8e7d7bb
hex775a5e3fc701

131230012000001 has 2 divisors, whose sum is σ = 131230012000002. Its totient is φ = 131230012000000.

The previous prime is 131230011999943. The next prime is 131230012000033. The reversal of 131230012000001 is 100000210032131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114745315781776 + 16484696218225 = 10711924^2 + 4060135^2 .

It is a cyclic number.

It is not a de Polignac number, because 131230012000001 - 242 = 126831965488897 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131230012000001.

It is not a weakly prime, because it can be changed into another prime (131230012003001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65615006000000 + 65615006000001.

It is an arithmetic number, because the mean of its divisors is an integer number (65615006000001).

Almost surely, 2131230012000001 is an apocalyptic number.

It is an amenable number.

131230012000001 is a deficient number, since it is larger than the sum of its proper divisors (1).

131230012000001 is an equidigital number, since it uses as much as digits as its factorization.

131230012000001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 131230012000001 its reverse (100000210032131), we get a palindrome (231230222032132).

The spelling of 131230012000001 in words is "one hundred thirty-one trillion, two hundred thirty billion, twelve million, one", and thus it is an aban number.