Base | Representation |
---|---|
bin | 1011111011110111000001… |
… | …1110110101100110010011 |
3 | 1201110112210021200211121221 |
4 | 2332331300132311212103 |
5 | 3210001412112040311 |
6 | 43524343435225511 |
7 | 2523051322260235 |
oct | 276756036654623 |
9 | 51415707624557 |
10 | 13123012221331 |
11 | 41aa490312331 |
12 | 157b3b22a8297 |
13 | 742657c4596c |
14 | 33522b436255 |
15 | 17b55dce7671 |
hex | bef707b5993 |
13123012221331 has 2 divisors, whose sum is σ = 13123012221332. Its totient is φ = 13123012221330.
The previous prime is 13123012221299. The next prime is 13123012221343. The reversal of 13123012221331 is 13312221032131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13123012221331 - 25 = 13123012221299 is a prime.
It is a super-2 number, since 2×131230122213312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13123012221296 and 13123012221305.
It is not a weakly prime, because it can be changed into another prime (13123012221391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561506110665 + 6561506110666.
It is an arithmetic number, because the mean of its divisors is an integer number (6561506110666).
Almost surely, 213123012221331 is an apocalyptic number.
13123012221331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123012221331 is an equidigital number, since it uses as much as digits as its factorization.
13123012221331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13123012221331 its reverse (13312221032131), we get a palindrome (26435233253462).
The spelling of 13123012221331 in words is "thirteen trillion, one hundred twenty-three billion, twelve million, two hundred twenty-one thousand, three hundred thirty-one".
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