13123041202433 has 2 divisors, whose sum is σ = 13123041202434. Its totient is φ = 13123041202432.

The previous prime is 13123041202399. The next prime is 13123041202459. The reversal of 13123041202433 is 33420214032131.

13123041202433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13120209685489 + 2831516944 = 3622183^2 + 53212^2 .

It is a cyclic number.

It is not a de Polignac number, because 13123041202433 - 2³⁸ = 12848163295489 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13123041202396 and 13123041202405.

It is not a weakly prime, because it can be changed into another prime (13123041202483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561520601216 + 6561520601217.

It is an arithmetic number, because the mean of its divisors is an integer number (6561520601217).

Almost surely, 2^{13123041202433} is an apocalyptic number.

It is an amenable number.

13123041202433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13123041202433 is an equidigital number, since it uses as much as digits as its factorization.

13123041202433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 13123041202433 its reverse (33420214032131), we get a palindrome (46543255234564).

The spelling of 13123041202433 in words is "thirteen trillion, one hundred twenty-three billion, forty-one million, two hundred two thousand, four hundred thirty-three".