Base | Representation |
---|---|
bin | 11101110101101010011001… |
… | …010100010110001111010001 |
3 | 122012122120011020100111011221 |
4 | 131311222121110112033101 |
5 | 114200042043232310001 |
6 | 1143034405052405041 |
7 | 36433061406511666 |
oct | 3565523124261721 |
9 | 565576136314157 |
10 | 131231003010001 |
11 | 388a5835017634 |
12 | 12875545476781 |
13 | 582c051c8720b |
14 | 2459886023a6d |
15 | 1028945e861a1 |
hex | 775a995163d1 |
131231003010001 has 2 divisors, whose sum is σ = 131231003010002. Its totient is φ = 131231003010000.
The previous prime is 131231003009993. The next prime is 131231003010007. The reversal of 131231003010001 is 100010300132131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 123006731905600 + 8224271104401 = 11090840^2 + 2867799^2 .
It is a cyclic number.
It is not a de Polignac number, because 131231003010001 - 23 = 131231003009993 is a prime.
It is not a weakly prime, because it can be changed into another prime (131231003010007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65615501505000 + 65615501505001.
It is an arithmetic number, because the mean of its divisors is an integer number (65615501505001).
Almost surely, 2131231003010001 is an apocalyptic number.
It is an amenable number.
131231003010001 is a deficient number, since it is larger than the sum of its proper divisors (1).
131231003010001 is an equidigital number, since it uses as much as digits as its factorization.
131231003010001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131231003010001 its reverse (100010300132131), we get a palindrome (231241303142132).
The spelling of 131231003010001 in words is "one hundred thirty-one trillion, two hundred thirty-one billion, three million, ten thousand, one".
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