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131231003010001 is a prime number
BaseRepresentation
bin11101110101101010011001…
…010100010110001111010001
3122012122120011020100111011221
4131311222121110112033101
5114200042043232310001
61143034405052405041
736433061406511666
oct3565523124261721
9565576136314157
10131231003010001
11388a5835017634
1212875545476781
13582c051c8720b
142459886023a6d
151028945e861a1
hex775a995163d1

131231003010001 has 2 divisors, whose sum is σ = 131231003010002. Its totient is φ = 131231003010000.

The previous prime is 131231003009993. The next prime is 131231003010007. The reversal of 131231003010001 is 100010300132131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123006731905600 + 8224271104401 = 11090840^2 + 2867799^2 .

It is a cyclic number.

It is not a de Polignac number, because 131231003010001 - 23 = 131231003009993 is a prime.

It is not a weakly prime, because it can be changed into another prime (131231003010007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65615501505000 + 65615501505001.

It is an arithmetic number, because the mean of its divisors is an integer number (65615501505001).

Almost surely, 2131231003010001 is an apocalyptic number.

It is an amenable number.

131231003010001 is a deficient number, since it is larger than the sum of its proper divisors (1).

131231003010001 is an equidigital number, since it uses as much as digits as its factorization.

131231003010001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 131231003010001 its reverse (100010300132131), we get a palindrome (231241303142132).

The spelling of 131231003010001 in words is "one hundred thirty-one trillion, two hundred thirty-one billion, three million, ten thousand, one".