Base | Representation |
---|---|
bin | 11000011100011001… |
… | …01010110110000100 |
3 | 1020212120102202120210 |
4 | 30032030222312010 |
5 | 203334003313012 |
6 | 10010105355420 |
7 | 643126354545 |
oct | 141614526604 |
9 | 36776382523 |
10 | 13123104132 |
11 | 5624717406 |
12 | 2662a98b70 |
13 | 1311a44798 |
14 | 8c6c524cc |
15 | 51c16c23c |
hex | 30e32ad84 |
13123104132 has 24 divisors (see below), whose sum is σ = 30622536000. Its totient is φ = 4374088096.
The previous prime is 13123104121. The next prime is 13123104143. The reversal of 13123104132 is 23140132131.
It is an interprime number because it is at equal distance from previous prime (13123104121) and next prime (13123104143).
It is a junction number, because it is equal to n+sod(n) for n = 13123104099 and 13123104108.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 259369 + ... + 305807.
It is an arithmetic number, because the mean of its divisors is an integer number (1275939000).
Almost surely, 213123104132 is an apocalyptic number.
13123104132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13123104132 is an abundant number, since it is smaller than the sum of its proper divisors (17499431868).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13123104132 is a wasteful number, since it uses less digits than its factorization.
13123104132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69995 (or 69993 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13123104132 its reverse (23140132131), we get a palindrome (36263236263).
The spelling of 13123104132 in words is "thirteen billion, one hundred twenty-three million, one hundred four thousand, one hundred thirty-two".
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