Base | Representation |
---|---|
bin | 10011000110001011111… |
… | …001000011010110100001 |
3 | 11122110022021120120122121 |
4 | 103012023321003112201 |
5 | 133000103333423431 |
6 | 2442511240504241 |
7 | 163545213033544 |
oct | 23061371032641 |
9 | 4573267516577 |
10 | 1312312014241 |
11 | 466603a13778 |
12 | 19240277b081 |
13 | 9699aaa5377 |
14 | 477327c685b |
15 | 24209c79611 |
hex | 1318be435a1 |
1312312014241 has 8 divisors (see below), whose sum is σ = 1323949989600. Its totient is φ = 1300674470592.
The previous prime is 1312312014229. The next prime is 1312312014257. The reversal of 1312312014241 is 1424102132131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1312312014241 - 215 = 1312311981473 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1312312024241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11593866 + ... + 11706508.
It is an arithmetic number, because the mean of its divisors is an integer number (165493748700).
Almost surely, 21312312014241 is an apocalyptic number.
It is an amenable number.
1312312014241 is a deficient number, since it is larger than the sum of its proper divisors (11637975359).
1312312014241 is a wasteful number, since it uses less digits than its factorization.
1312312014241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 215855.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1312312014241 its reverse (1424102132131), we get a palindrome (2736414146372).
The spelling of 1312312014241 in words is "one trillion, three hundred twelve billion, three hundred twelve million, fourteen thousand, two hundred forty-one".
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