Base | Representation |
---|---|
bin | 11101110101101010101101… |
… | …000011000011111110001011 |
3 | 122012122121000022012200201112 |
4 | 131311222231003003332023 |
5 | 114200043233002214201 |
6 | 1143034501555240535 |
7 | 36433102536206423 |
oct | 3565525503037613 |
9 | 565577008180645 |
10 | 131231334023051 |
11 | 388a5994953639 |
12 | 128756182a914b |
13 | 582c0a5723122 |
14 | 24598b7d8b483 |
15 | 102896506e0bb |
hex | 775aad0c3f8b |
131231334023051 has 2 divisors, whose sum is σ = 131231334023052. Its totient is φ = 131231334023050.
The previous prime is 131231334023039. The next prime is 131231334023059. The reversal of 131231334023051 is 150320433132131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131231334023051 - 210 = 131231334022027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131231334022999 and 131231334023017.
It is not a weakly prime, because it can be changed into another prime (131231334023059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65615667011525 + 65615667011526.
It is an arithmetic number, because the mean of its divisors is an integer number (65615667011526).
Almost surely, 2131231334023051 is an apocalyptic number.
131231334023051 is a deficient number, since it is larger than the sum of its proper divisors (1).
131231334023051 is an equidigital number, since it uses as much as digits as its factorization.
131231334023051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 32.
Adding to 131231334023051 its reverse (150320433132131), we get a palindrome (281551767155182).
The spelling of 131231334023051 in words is "one hundred thirty-one trillion, two hundred thirty-one billion, three hundred thirty-four million, twenty-three thousand, fifty-one".
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