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131232111217 is a prime number
BaseRepresentation
bin111101000111000001…
…0110001101001110001
3110112201210100222110121
41322032002301221301
54122230410024332
6140142011330241
712324024353224
oct1721602615161
9415653328417
10131232111217
1150723118569
1221525450981
13c4b522cc1c
1464ccd975bb
1536310e3797
hex1e8e0b1a71

131232111217 has 2 divisors, whose sum is σ = 131232111218. Its totient is φ = 131232111216.

The previous prime is 131232111187. The next prime is 131232111259. The reversal of 131232111217 is 712111232131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103040358001 + 28191753216 = 320999^2 + 167904^2 .

It is a cyclic number.

It is not a de Polignac number, because 131232111217 - 27 = 131232111089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131232111191 and 131232111200.

It is not a weakly prime, because it can be changed into another prime (131232111277) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65616055608 + 65616055609.

It is an arithmetic number, because the mean of its divisors is an integer number (65616055609).

Almost surely, 2131232111217 is an apocalyptic number.

It is an amenable number.

131232111217 is a deficient number, since it is larger than the sum of its proper divisors (1).

131232111217 is an equidigital number, since it uses as much as digits as its factorization.

131232111217 is an evil number, because the sum of its binary digits is even.

The product of its digits is 504, while the sum is 25.

Adding to 131232111217 its reverse (712111232131), we get a palindrome (843343343348).

The spelling of 131232111217 in words is "one hundred thirty-one billion, two hundred thirty-two million, one hundred eleven thousand, two hundred seventeen".