Base | Representation |
---|---|
bin | 111101000111000001… |
… | …0110001101001110001 |
3 | 110112201210100222110121 |
4 | 1322032002301221301 |
5 | 4122230410024332 |
6 | 140142011330241 |
7 | 12324024353224 |
oct | 1721602615161 |
9 | 415653328417 |
10 | 131232111217 |
11 | 50723118569 |
12 | 21525450981 |
13 | c4b522cc1c |
14 | 64ccd975bb |
15 | 36310e3797 |
hex | 1e8e0b1a71 |
131232111217 has 2 divisors, whose sum is σ = 131232111218. Its totient is φ = 131232111216.
The previous prime is 131232111187. The next prime is 131232111259. The reversal of 131232111217 is 712111232131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 103040358001 + 28191753216 = 320999^2 + 167904^2 .
It is a cyclic number.
It is not a de Polignac number, because 131232111217 - 27 = 131232111089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131232111191 and 131232111200.
It is not a weakly prime, because it can be changed into another prime (131232111277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65616055608 + 65616055609.
It is an arithmetic number, because the mean of its divisors is an integer number (65616055609).
Almost surely, 2131232111217 is an apocalyptic number.
It is an amenable number.
131232111217 is a deficient number, since it is larger than the sum of its proper divisors (1).
131232111217 is an equidigital number, since it uses as much as digits as its factorization.
131232111217 is an evil number, because the sum of its binary digits is even.
The product of its digits is 504, while the sum is 25.
Adding to 131232111217 its reverse (712111232131), we get a palindrome (843343343348).
The spelling of 131232111217 in words is "one hundred thirty-one billion, two hundred thirty-two million, one hundred eleven thousand, two hundred seventeen".
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