13123301250113 has 4 divisors (see below), whose sum is σ = 13125717624768. Its totient is φ = 13120884875460.

The previous prime is 13123301250079. The next prime is 13123301250149. The reversal of 13123301250113 is 31105210332131.

13123301250113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13123301250113 - 2²² = 13123297055809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13123301210113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1208179181 + ... + 1208190042.

It is an arithmetic number, because the mean of its divisors is an integer number (3281429406192).

Almost surely, 2^{13123301250113} is an apocalyptic number.

It is an amenable number.

13123301250113 is a deficient number, since it is larger than the sum of its proper divisors (2416374655).

13123301250113 is an equidigital number, since it uses as much as digits as its factorization.

13123301250113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2416374654.

The product of its (nonzero) digits is 1620, while the sum is 26.

Adding to 13123301250113 its reverse (31105210332131), we get a palindrome (44228511582244).

The spelling of 13123301250113 in words is "thirteen trillion, one hundred twenty-three billion, three hundred one million, two hundred fifty thousand, one hundred thirteen".