13123323121 has 4 divisors (see below), whose sum is σ = 13173221952. Its totient is φ = 13073424292.

The previous prime is 13123323119. The next prime is 13123323151. The reversal of 13123323121 is 12132332131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12132332131 = 53 ⋅228911927.

It is a cyclic number.

It is not a de Polignac number, because 13123323121 - 2¹ = 13123323119 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13123323092 and 13123323101.

It is not an unprimeable number, because it can be changed into a prime (13123323151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24949021 + ... + 24949546.

It is an arithmetic number, because the mean of its divisors is an integer number (3293305488).

Almost surely, 2^13123323121 is an apocalyptic number.

It is an amenable number.

13123323121 is a deficient number, since it is larger than the sum of its proper divisors (49898831).

13123323121 is an equidigital number, since it uses as much as digits as its factorization.

13123323121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49898830.

The product of its digits is 648, while the sum is 22.

Adding to 13123323121 its reverse (12132332131), we get a palindrome (25255655252).

The spelling of 13123323121 in words is "thirteen billion, one hundred twenty-three million, three hundred twenty-three thousand, one hundred twenty-one".