Base | Representation |
---|---|
bin | 1011111011111000001110… |
… | …1110010001001011010001 |
3 | 1201110120121210010101202011 |
4 | 2332332003232101023101 |
5 | 3210003042232033203 |
6 | 43524435450222521 |
7 | 2523062322160603 |
oct | 276760356211321 |
9 | 51416553111664 |
10 | 13123335033553 |
11 | 41aa636557998 |
12 | 157b482424a41 |
13 | 7426a9a9cc04 |
14 | 33525c267173 |
15 | 17b57c31076d |
hex | bef83b912d1 |
13123335033553 has 2 divisors, whose sum is σ = 13123335033554. Its totient is φ = 13123335033552.
The previous prime is 13123335033509. The next prime is 13123335033649. The reversal of 13123335033553 is 35533053332131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13108114383169 + 15220650384 = 3620513^2 + 123372^2 .
It is an emirp because it is prime and its reverse (35533053332131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13123335033553 - 241 = 10924311778001 is a prime.
It is not a weakly prime, because it can be changed into another prime (13123335033503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561667516776 + 6561667516777.
It is an arithmetic number, because the mean of its divisors is an integer number (6561667516777).
Almost surely, 213123335033553 is an apocalyptic number.
It is an amenable number.
13123335033553 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123335033553 is an equidigital number, since it uses as much as digits as its factorization.
13123335033553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 546750, while the sum is 40.
Adding to 13123335033553 its reverse (35533053332131), we get a palindrome (48656388365684).
The spelling of 13123335033553 in words is "thirteen trillion, one hundred twenty-three billion, three hundred thirty-five million, thirty-three thousand, five hundred fifty-three".
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