Base | Representation |
---|---|
bin | 1011111011111000001110… |
… | …1110010011010011101011 |
3 | 1201110120121210010211201111 |
4 | 2332332003232103103223 |
5 | 3210003042232323113 |
6 | 43524435450331151 |
7 | 2523062322225214 |
oct | 276760356232353 |
9 | 51416553124644 |
10 | 13123335042283 |
11 | 41aa636563504 |
12 | 157b482429ab7 |
13 | 7426a9aa3b8b |
14 | 33525c26a40b |
15 | 17b57c31313d |
hex | bef83b934eb |
13123335042283 has 2 divisors, whose sum is σ = 13123335042284. Its totient is φ = 13123335042282.
The previous prime is 13123335042247. The next prime is 13123335042359. The reversal of 13123335042283 is 38224053332131.
It is a weak prime.
It is an emirp because it is prime and its reverse (38224053332131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13123335042283 - 221 = 13123332945131 is a prime.
It is not a weakly prime, because it can be changed into another prime (13123335042683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561667521141 + 6561667521142.
It is an arithmetic number, because the mean of its divisors is an integer number (6561667521142).
Almost surely, 213123335042283 is an apocalyptic number.
13123335042283 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123335042283 is an equidigital number, since it uses as much as digits as its factorization.
13123335042283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 40.
The spelling of 13123335042283 in words is "thirteen trillion, one hundred twenty-three billion, three hundred thirty-five million, forty-two thousand, two hundred eighty-three".
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