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13123443230234 = 29757967245223
BaseRepresentation
bin1011111011111000101000…
…1011000000011000011010
31201110120220022201100200122
42332332022023000120122
53210003302431331414
643524454313233242
72523065104632041
oct276761213003032
951416808640618
1013123443230234
1141aa691637737
12157b4b2702822
137426c632350c
1433526c78d558
1517b586a83b8e
hexbef8a2c061a

13123443230234 has 8 divisors (see below), whose sum is σ = 19685366873760. Its totient is φ = 6561654272316.

The previous prime is 13123443230231. The next prime is 13123443230239. The reversal of 13123443230234 is 43203234432131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13123443230194 and 13123443230203.

It is not an unprimeable number, because it can be changed into a prime (13123443230231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33427454 + ... + 33817769.

It is an arithmetic number, because the mean of its divisors is an integer number (2460670859220).

Almost surely, 213123443230234 is an apocalyptic number.

13123443230234 is a deficient number, since it is larger than the sum of its proper divisors (6561923643526).

13123443230234 is an equidigital number, since it uses as much as digits as its factorization.

13123443230234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67342804.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 13123443230234 its reverse (43203234432131), we get a palindrome (56326677662365).

The spelling of 13123443230234 in words is "thirteen trillion, one hundred twenty-three billion, four hundred forty-three million, two hundred thirty thousand, two hundred thirty-four".

Divisors: 1 2 97579 195158 67245223 134490446 6561721615117 13123443230234