13123443340003 has 4 divisors (see below), whose sum is σ = 13127368991968. Its totient is φ = 13119517688040.

The previous prime is 13123443339959. The next prime is 13123443340061. The reversal of 13123443340003 is 30004334432131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13123443340003 - 2⁹ = 13123443339491 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13123443340093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1962820968 + ... + 1962827653.

It is an arithmetic number, because the mean of its divisors is an integer number (3281842247992).

Almost surely, 2^{13123443340003} is an apocalyptic number.

13123443340003 is a deficient number, since it is larger than the sum of its proper divisors (3925651965).

13123443340003 is an equidigital number, since it uses as much as digits as its factorization.

13123443340003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3925651964.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 13123443340003 its reverse (30004334432131), we get a palindrome (43127777772134).

The spelling of 13123443340003 in words is "thirteen trillion, one hundred twenty-three billion, four hundred forty-three million, three hundred forty thousand, three".