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131235030051 = 343745010017
BaseRepresentation
bin111101000111000110…
…1111010010000100011
3110112201222212021100120
41322032031322100203
54122232131430201
6140142154051323
712324061231026
oct1721615722043
9415658767316
10131235030051
1150724831524
1221526419b43
13c4b5a12648
1464cd5171bd
1536314bd536
hex1e8e37a423

131235030051 has 4 divisors (see below), whose sum is σ = 174980040072. Its totient is φ = 87490020032.

The previous prime is 131235030029. The next prime is 131235030071. The reversal of 131235030051 is 150030532131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131235030051 - 25 = 131235030019 is a prime.

It is a super-2 number, since 2×1312350300512 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (131235030071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21872505006 + ... + 21872505011.

It is an arithmetic number, because the mean of its divisors is an integer number (43745010018).

Almost surely, 2131235030051 is an apocalyptic number.

131235030051 is a deficient number, since it is larger than the sum of its proper divisors (43745010021).

131235030051 is an equidigital number, since it uses as much as digits as its factorization.

131235030051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43745010020.

The product of its (nonzero) digits is 1350, while the sum is 24.

Adding to 131235030051 its reverse (150030532131), we get a palindrome (281265562182).

The spelling of 131235030051 in words is "one hundred thirty-one billion, two hundred thirty-five million, thirty thousand, fifty-one".

Divisors: 1 3 43745010017 131235030051