Base | Representation |
---|---|
bin | 11000011100011101… |
… | …10110011110010011 |
3 | 1020212121111211002222 |
4 | 30032032312132103 |
5 | 203334130113201 |
6 | 10010125531255 |
7 | 643134256133 |
oct | 141616663623 |
9 | 36777454088 |
10 | 13123676051 |
11 | 5624a78072 |
12 | 2663113b2b |
13 | 1311bb4bb5 |
14 | 8c6d60ac3 |
15 | 51c23191b |
hex | 30e3b6793 |
13123676051 has 2 divisors, whose sum is σ = 13123676052. Its totient is φ = 13123676050.
The previous prime is 13123676011. The next prime is 13123676063. The reversal of 13123676051 is 15067632131.
It is a strong prime.
It is an emirp because it is prime and its reverse (15067632131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13123676051 - 210 = 13123675027 is a prime.
It is not a weakly prime, because it can be changed into another prime (13123676011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561838025 + 6561838026.
It is an arithmetic number, because the mean of its divisors is an integer number (6561838026).
Almost surely, 213123676051 is an apocalyptic number.
13123676051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123676051 is an equidigital number, since it uses as much as digits as its factorization.
13123676051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 22680, while the sum is 35.
The spelling of 13123676051 in words is "thirteen billion, one hundred twenty-three million, six hundred seventy-six thousand, fifty-one".
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