Base | Representation |
---|---|
bin | 111101000111010000… |
… | …1110100110111101001 |
3 | 110112202100200111221202 |
4 | 1322032201310313221 |
5 | 4122240001011412 |
6 | 140142502013545 |
7 | 12324153504032 |
oct | 1721641646751 |
9 | 415670614852 |
10 | 131240250857 |
11 | 50727777a41 |
12 | 215281172b5 |
13 | c4b6b1ca91 |
14 | 64d00b5a89 |
15 | 3631ba03c2 |
hex | 1e8e874de9 |
131240250857 has 4 divisors (see below), whose sum is σ = 131354274816. Its totient is φ = 131126226900.
The previous prime is 131240250833. The next prime is 131240250863. The reversal of 131240250857 is 758052042131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131240250857 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 131240250857.
It is not an unprimeable number, because it can be changed into a prime (131240250887) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57010253 + ... + 57012554.
It is an arithmetic number, because the mean of its divisors is an integer number (32838568704).
Almost surely, 2131240250857 is an apocalyptic number.
It is an amenable number.
131240250857 is a deficient number, since it is larger than the sum of its proper divisors (114023959).
131240250857 is a wasteful number, since it uses less digits than its factorization.
131240250857 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 114023958.
The product of its (nonzero) digits is 67200, while the sum is 38.
Adding to 131240250857 its reverse (758052042131), we get a palindrome (889292292988).
The spelling of 131240250857 in words is "one hundred thirty-one billion, two hundred forty million, two hundred fifty thousand, eight hundred fifty-seven".
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