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13124140324411 = 73917759323849
BaseRepresentation
bin1011111011111011001110…
…1110001101011000111011
31201110122200220102102010111
42332332303232031120323
53210011214410340121
643525051414325151
72523121301061424
oct276766356153073
951418626372114
1013124140324411
1141aaa0a081926
12157b6680597b7
137427a788608c
143352d71ac64b
1517b5c7d802e1
hexbefb3b8d63b

13124140324411 has 4 divisors (see below), whose sum is σ = 13141899649000. Its totient is φ = 13106380999824.

The previous prime is 13124140324313. The next prime is 13124140324417. The reversal of 13124140324411 is 11442304142131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13124140324411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13124140324417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8879661186 + ... + 8879662663.

It is an arithmetic number, because the mean of its divisors is an integer number (3285474912250).

Almost surely, 213124140324411 is an apocalyptic number.

13124140324411 is a deficient number, since it is larger than the sum of its proper divisors (17759324589).

13124140324411 is an equidigital number, since it uses as much as digits as its factorization.

13124140324411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17759324588.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 13124140324411 its reverse (11442304142131), we get a palindrome (24566444466542).

The spelling of 13124140324411 in words is "thirteen trillion, one hundred twenty-four billion, one hundred forty million, three hundred twenty-four thousand, four hundred eleven".

Divisors: 1 739 17759323849 13124140324411