Base | Representation |
---|---|
bin | 11101110101110100000101… |
… | …010001000001011010111011 |
3 | 122012200120000002200010221022 |
4 | 131311310011101001122323 |
5 | 114200224343411342334 |
6 | 1143043245122133055 |
7 | 36433610223541424 |
oct | 3565640521013273 |
9 | 565616002603838 |
10 | 131241404012219 |
11 | 388aa192121536 |
12 | 128775687b118b |
13 | 583001ba771b7 |
14 | 245a19152c64b |
15 | 1028d5415482e |
hex | 775d054416bb |
131241404012219 has 2 divisors, whose sum is σ = 131241404012220. Its totient is φ = 131241404012218.
The previous prime is 131241404012207. The next prime is 131241404012239. The reversal of 131241404012219 is 912210404142131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131241404012219 is a prime.
It is a super-2 number, since 2×1312414040122192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131241404012239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65620702006109 + 65620702006110.
It is an arithmetic number, because the mean of its divisors is an integer number (65620702006110).
Almost surely, 2131241404012219 is an apocalyptic number.
131241404012219 is a deficient number, since it is larger than the sum of its proper divisors (1).
131241404012219 is an equidigital number, since it uses as much as digits as its factorization.
131241404012219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 35.
The spelling of 131241404012219 in words is "one hundred thirty-one trillion, two hundred forty-one billion, four hundred four million, twelve thousand, two hundred nineteen".
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