Base | Representation |
---|---|
bin | 11101110101110100000111… |
… | …011011001110011000110011 |
3 | 122012200120002121211202202112 |
4 | 131311310013123032120303 |
5 | 114200224432200204303 |
6 | 1143043252454435535 |
7 | 36433611143512325 |
oct | 3565640733163063 |
9 | 565616077752675 |
10 | 131241440241203 |
11 | 388aa200616946 |
12 | 12877578962bab |
13 | 5830026420476 |
14 | 245a19627d615 |
15 | 1028d5740e0d8 |
hex | 775d076ce633 |
131241440241203 has 2 divisors, whose sum is σ = 131241440241204. Its totient is φ = 131241440241202.
The previous prime is 131241440241181. The next prime is 131241440241323. The reversal of 131241440241203 is 302142044142131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131241440241203 - 216 = 131241440175667 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131241440241203.
It is not a weakly prime, because it can be changed into another prime (131241430241203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65620720120601 + 65620720120602.
It is an arithmetic number, because the mean of its divisors is an integer number (65620720120602).
Almost surely, 2131241440241203 is an apocalyptic number.
131241440241203 is a deficient number, since it is larger than the sum of its proper divisors (1).
131241440241203 is an equidigital number, since it uses as much as digits as its factorization.
131241440241203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 131241440241203 its reverse (302142044142131), we get a palindrome (433383484383334).
The spelling of 131241440241203 in words is "one hundred thirty-one trillion, two hundred forty-one billion, four hundred forty million, two hundred forty-one thousand, two hundred three".
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