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13124204034397 = 107349826342533
BaseRepresentation
bin1011111011111011011110…
…0001001111100101011101
31201110122212100022012210121
42332332313201033211131
53210011332213100042
643525102012034541
72523123003440011
oct276766741174535
951418770265717
1013124204034397
1141aaa42037105
12157b685462a51
137427b7b318b1
14335301834541
1517b5cd767367
hexbefb784f95d

13124204034397 has 16 divisors (see below), whose sum is σ = 13286736892800. Its totient is φ = 12962420476992.

The previous prime is 13124204034371. The next prime is 13124204034401. The reversal of 13124204034397 is 79343040242131.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13124204034397 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13124204031397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 308543943 + ... + 308586475.

It is an arithmetic number, because the mean of its divisors is an integer number (830421055800).

Almost surely, 213124204034397 is an apocalyptic number.

It is an amenable number.

13124204034397 is a deficient number, since it is larger than the sum of its proper divisors (162532858403).

13124204034397 is a wasteful number, since it uses less digits than its factorization.

13124204034397 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51252.

The product of its (nonzero) digits is 435456, while the sum is 43.

The spelling of 13124204034397 in words is "thirteen trillion, one hundred twenty-four billion, two hundred four million, thirty-four thousand, three hundred ninety-seven".

Divisors: 1 107 349 8263 37343 42533 884141 2883787 4551031 14844017 308565209 351450179 1588309819 37605169153 122656112471 13124204034397