Base | Representation |
---|---|
bin | 11101110101110100110001… |
… | …110010100110001111011011 |
3 | 122012200121221011021122000121 |
4 | 131311310301302212033123 |
5 | 114200232411124330131 |
6 | 1143043451205014111 |
7 | 36433634564121325 |
oct | 3565646162461733 |
9 | 565617834248017 |
10 | 131242151011291 |
11 | 388aa535851a41 |
12 | 128777369b4337 |
13 | 583010a760a98 |
14 | 245a22281c615 |
15 | 1028d99a0c911 |
hex | 775d31ca63db |
131242151011291 has 2 divisors, whose sum is σ = 131242151011292. Its totient is φ = 131242151011290.
The previous prime is 131242151011277. The next prime is 131242151011369. The reversal of 131242151011291 is 192110151242131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131242151011291 - 29 = 131242151010779 is a prime.
It is a super-2 number, since 2×1312421510112912 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131242151014291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65621075505645 + 65621075505646.
It is an arithmetic number, because the mean of its divisors is an integer number (65621075505646).
Almost surely, 2131242151011291 is an apocalyptic number.
131242151011291 is a deficient number, since it is larger than the sum of its proper divisors (1).
131242151011291 is an equidigital number, since it uses as much as digits as its factorization.
131242151011291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 34.
The spelling of 131242151011291 in words is "one hundred thirty-one trillion, two hundred forty-two billion, one hundred fifty-one million, eleven thousand, two hundred ninety-one".
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