Base | Representation |
---|---|
bin | 11101110101110101101010… |
… | …100011000110111000100000 |
3 | 122012200201101112002110201000 |
4 | 131311311222203012320200 |
5 | 114200241333413031000 |
6 | 1143044125502512000 |
7 | 36434000306046315 |
oct | 3565655243067040 |
9 | 565621345073630 |
10 | 131243103252000 |
11 | 388aa984315533 |
12 | 12877961895600 |
13 | 583022cb1871c |
14 | 245a2b3096d0c |
15 | 1028e03408000 |
hex | 775d6a8c6e20 |
131243103252000 has 1536 divisors, whose sum is σ = 502473026764800. Its totient is φ = 33232550400000.
The previous prime is 131243103251999. The next prime is 131243103252077. The reversal of 131243103252000 is 252301342131.
131243103252000 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 4 + 310 + 325 + 20 + 0 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 54435130795 + ... + 54435133205.
It is an arithmetic number, because the mean of its divisors is an integer number (327130876800).
Almost surely, 2131243103252000 is an apocalyptic number.
131243103252000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131243103252000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (251236513382400).
131243103252000 is an abundant number, since it is smaller than the sum of its proper divisors (371229923512800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131243103252000 is a wasteful number, since it uses less digits than its factorization.
131243103252000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2776 (or 2752 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 27.
Adding to 131243103252000 its reverse (252301342131), we get a palindrome (131495404594131).
The spelling of 131243103252000 in words is "one hundred thirty-one trillion, two hundred forty-three billion, one hundred three million, two hundred fifty-two thousand".
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