Base | Representation |
---|---|
bin | 1011111011111011110111… |
… | …1001011100010110100010 |
3 | 1201110200010210122201212111 |
4 | 2332332331321130112202 |
5 | 3210012042111311232 |
6 | 43525120353345534 |
7 | 2523125443124626 |
oct | 276767571342642 |
9 | 51420123581774 |
10 | 13124311041442 |
11 | 41aaa97484087 |
12 | 157b6b52682aa |
13 | 742804059883 |
14 | 335311b2b186 |
15 | 17b5d7d53047 |
hex | befbde5c5a2 |
13124311041442 has 4 divisors (see below), whose sum is σ = 19686466562166. Its totient is φ = 6562155520720.
The previous prime is 13124311041427. The next prime is 13124311041451. The reversal of 13124311041442 is 24414011342131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9046734512841 + 4077576528601 = 3007779^2 + 2019301^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3281077760359 + ... + 3281077760362.
Almost surely, 213124311041442 is an apocalyptic number.
13124311041442 is a deficient number, since it is larger than the sum of its proper divisors (6562155520724).
13124311041442 is an equidigital number, since it uses as much as digits as its factorization.
13124311041442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6562155520723.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 13124311041442 its reverse (24414011342131), we get a palindrome (37538322383573).
The spelling of 13124311041442 in words is "thirteen trillion, one hundred twenty-four billion, three hundred eleven million, forty-one thousand, four hundred forty-two".
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