13124311441 has 4 divisors (see below), whose sum is σ = 13155634800. Its totient is φ = 13092988084.

The previous prime is 13124311439. The next prime is 13124311469. The reversal of 13124311441 is 14411342131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13124311441 - 2¹ = 13124311439 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13124311471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15661051 + ... + 15661888.

It is an arithmetic number, because the mean of its divisors is an integer number (3288908700).

Almost surely, 2^13124311441 is an apocalyptic number.

It is an amenable number.

13124311441 is a deficient number, since it is larger than the sum of its proper divisors (31323359).

13124311441 is an equidigital number, since it uses as much as digits as its factorization.

13124311441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31323358.

The product of its digits is 1152, while the sum is 25.

Adding to 13124311441 its reverse (14411342131), we get a palindrome (27535653572).

The spelling of 13124311441 in words is "thirteen billion, one hundred twenty-four million, three hundred eleven thousand, four hundred forty-one".