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131243312130419 = 421311741834039
BaseRepresentation
bin11101110101110101110110…
…111111111010100101110011
3122012200201221002010121000202
4131311311312333322211303
5114200242300401133134
61143044202323505415
736434005423352306
oct3565656677724563
9565621832117022
10131243312130419
11388aaa81211a25
12128779bb82826b
135830264190c18
14245a2d2b0ab3d
151028e16917d7e
hex775d76ffa973

131243312130419 has 4 divisors (see below), whose sum is σ = 131555053964880. Its totient is φ = 130931570295960.

The previous prime is 131243312130389. The next prime is 131243312130443. The reversal of 131243312130419 is 914031213342131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131243312130419 - 236 = 131174592653683 is a prime.

It is a super-2 number, since 2×1312433121304192 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131243312130919) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155870916599 + ... + 155870917440.

It is an arithmetic number, because the mean of its divisors is an integer number (32888763491220).

Almost surely, 2131243312130419 is an apocalyptic number.

131243312130419 is a deficient number, since it is larger than the sum of its proper divisors (311741834461).

131243312130419 is an equidigital number, since it uses as much as digits as its factorization.

131243312130419 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 311741834460.

The product of its (nonzero) digits is 46656, while the sum is 38.

The spelling of 131243312130419 in words is "one hundred thirty-one trillion, two hundred forty-three billion, three hundred twelve million, one hundred thirty thousand, four hundred nineteen".

Divisors: 1 421 311741834039 131243312130419